hello friends, please help me with the question, the conclusion of devison jurmers experiment of photo electric effect
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Electromagnetic radiation can push electrons free from the surface of a solid.This process is called the photoelectric effect.A material that can exhibit the photoelectric effect is said to be photoemissive.Electrons ejected by the photoelectric effect are called photoelectrons.The photoelectric effect will not occur when the frequency of the incident light is less than the threshold frequency.Different materials have different threshold frequencies.Most elements have threshold frequencies in the ultraviolet region of the electromagnetic spectrum.The maximum kinetic energy of a stream of photoelectrons…is determined by measuring the stopping potential (the applied voltage needed keep the photoelectrons trapped in the photoemissive surface).increases linearly with the frequency of the incident light above the threshold frequency.is independent of the intensity of the incident light.The rate at which photoelectrons are emitted from a photoemissive surface…is determined by measuring the electric current.is directly proportional to the intensity of the incident light when frequency is constant.On a graph of maximum kinetic energy vs. frequency…all curves are linear with slope equal to Planck's Constant.the intercept on the energy-axis is the threshold frequency of the material.Classical physics cannot explain why…no photoelectrons are emitted when the incident light has a frequency below the threshold,the maximum kinetic energy of the photoelectrons increases with the frequency of the incident light,the maximum kinetic energy of the photoelectrons is independent of the intensity of the incident light, andthere is essentially no delay between absorption of the radiant energy and the emission of photoelectrons.Modern physics states that…electromagnetic radiation is composed of discrete entities called photonsthe energy of a photon is proportional to its frequencythe work function of a material is the energy needed per photon to extract an electron from its surfaceEquationsphotoelectric effect
Kmax = E − ϕ = h(ƒ − ƒ0)
photon energyE = hf = hcλwork functionϕ = hf0 = hcλ0stopping potential
Kmax = eV0
Kmax = E − ϕ = h(ƒ − ƒ0)
photon energyE = hf = hcλwork functionϕ = hf0 = hcλ0stopping potential
Kmax = eV0
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