Question

Hello friends...please please help me in this question

Answer 1

HEY!!!


,

From the equation, 1 mole (28 g) of dinitrogen reacts with 3 mole (6 g) of
dihydrogen to give 2 mole (34 g) of ammonia.
⇒ 2.00 × 103g of dinitrogen will react with dihydrogen i.e.,2.00 × 103g of dinitrogen will react with 428.6 g of dihydrogen.
Given,
Amount of dihydrogen = 1.00 × 103g
Hence, N2 is the limiting reagent.
28 g of N2 produces 34 g of NH3.
Hence, mass of ammonia produced by 2000 g of N2= 2428.57 g

(ii) N2 is the limiting reagent and H2 is the excess reagent. Hence, H2 willremain unreacted.

(iii) Mass of dihydrogen left unreacted = 1.00 × 103g – 428.6 g= 571.4 g

Answer 2

Answer:

yes?

Explanation: