hello friends!!!
please tell answer
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heya!!
refer to given attachment please
the question is from the chapter :-
POWER AND EXPONENT
refer to given attachment please
the question is from the chapter :-
POWER AND EXPONENT
Attachments:
nitthesh7:
Hey I've used another method pls check it
okay bhai
Answered by
6
》 (2)^n-5 × (5)^n-4 = 5 × 1
》 (2)^n-5 × (5)^n-4 / 5^1 = 1
by the formula a^m/a^n = a^m-n
》 (2)^n-5 × (5)^n-4-1 = 1
》 (2)^n-5 × (5)^n-5 = 1
by the formula a^m × b^m = (ab )^m
》 (2×5)^n-5 = 1
》 10^n-5 = 1
by the formula a^0 = 1
》 10^n-5 = 10^0
Taking only powers
》 n - 5 = 0
》 n = 5
Hence n = 5
☺ Hope this Helps ☺
》 (2)^n-5 × (5)^n-4 / 5^1 = 1
by the formula a^m/a^n = a^m-n
》 (2)^n-5 × (5)^n-4-1 = 1
》 (2)^n-5 × (5)^n-5 = 1
by the formula a^m × b^m = (ab )^m
》 (2×5)^n-5 = 1
》 10^n-5 = 1
by the formula a^0 = 1
》 10^n-5 = 10^0
Taking only powers
》 n - 5 = 0
》 n = 5
Hence n = 5
☺ Hope this Helps ☺
If u find it as most helpful pls mark it as brainliest
nice answer
Thanks
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