Question

hello friends pls solve this Question..

Answer 1

$a = log(2) \\ b = log(3) \\ c = log(7) \\ now \\ \\ {6}^{x} = {7}^{x + 4} \\ taking \: log \: both \: sides \\ log( {6}^{x} ) = log( {7}^{x + 4} ) \\ by \: property \: of \: log \\ \: \: \: \: \: \: \: \: log( {a}^{m} ) = m log(a) \\ x log(6) = (x + 4) log(7 ) \\ \\ xlog(3 \times 2) = (x + 4) log(7) \\ x( log(3) + log(2) ) = (x + 4) log(7) \\ x(b + a) = (x + 4)c \\ xb + xa = xc + 4c \\ x(a + b - c) = 4c \\ x = \frac{4c}{a + b - c}$
hope it will help you!!