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in an AP, the first term is 25 , nth term is -17 and the sum to first n terms is 60. find the common difference.
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Answers
Answered by
1
Answer:
d = -3
Step-by-step explanation:
Let 'a' be the first term and 'd' be the common difference.
First term (a) = 25.
nth term (an) = l = -17.
Sum to first n terms (Sn) = 60.
(i)
We know that Sum of n terms of an AP sn = (n/2)[a + l]
60 = (n/2)[25 - 17]
60 = (n/2)[8]
60 = 4n
n = 15.
(ii)
We know that nth term of an AP an = a + (n - 1) * d
-17 = 25 + (15 - 1) * d
-17 - 25 = 14d
-42 = 14d
d = -3.
Therefore, Common difference = -3.
Hope it helps!
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Answered by
1
Answer:
-3
Step-by-step explanation:
Sn=n/2(a+an)
60=n/2(25+(-17))
60=n/2(8)
60×2/8=n
n=15
now
an=a+(n-1)d
-17=25+(15-1)d
-17-25=14d
d=-42/14=-3
so,
n=15
d=-3
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