Question

Hello friends..... solve this.

Answer 1

Hello friend

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The conjugate pair of, 3√2 + √5 is 3√2 - √5

$\frac{8}{3 \sqrt{2} + \sqrt{5} } = \frac{8}{3 \sqrt{2} + \sqrt{5} } \times \frac{3 \sqrt{2} - \sqrt{5} }{3 \sqrt{2 - \sqrt{5} } } \\ \\ = \frac{8(3 \sqrt{2 } - \sqrt{5} )}{(3 \sqrt{2} ) {}^{2} - ( \sqrt{5}) {}^{2} } \\ \\ = \frac{8 \times 3 \sqrt{2} - 8 \sqrt{5} }{9 \times 2 - 5} \\ \\ = \frac{24 \sqrt{2} - 8 \sqrt{5} }{18 - 5} \\ \\ = \frac{24 \sqrt{2} - 8 \sqrt{5} }{13}$


This is the rationalizing solution of the denominator...

Thanks..

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