Math, asked by riyansh5, 1 year ago

Hello friends
Solve this equation by factorisation method​

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Answers

Answered by Ashishkumar098
7

Answer :-

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1. ax² + ( 4a² - 3b )x - 12ab = 0

ax² + 4a²x - 3bx - 12ab = 0

ax ( x + 4a ) - 3b ( x + 4a ) = 0

( x + 4a ) ( ax - 3b ) = 0

x = -4a , and x = 3b / a

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2. 4x² - 4ax + ( a² - b² ) = 0

4x ( x - a + b ) + ( a + b ) ( x - a + b ) = 0

( x - a + b ) ( 4x + a + b ) = 0

x = ( a - b ) , x = - ( a + b ) / 4

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Thanks!


riyansh5: can u explain me second question
Answered by lakshmisathish1
1

Answer:

hii

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aur

mera naam lakshita nhi hai (╥﹏╥)

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