Hello friends
Solve this equation by factorisation method
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Answer :-
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1. ax² + ( 4a² - 3b )x - 12ab = 0
ax² + 4a²x - 3bx - 12ab = 0
ax ( x + 4a ) - 3b ( x + 4a ) = 0
( x + 4a ) ( ax - 3b ) = 0
x = -4a , and x = 3b / a
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2. 4x² - 4ax + ( a² - b² ) = 0
4x ( x - a + b ) + ( a + b ) ( x - a + b ) = 0
( x - a + b ) ( 4x + a + b ) = 0
x = ( a - b ) , x = - ( a + b ) / 4
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Thanks!
riyansh5:
can u explain me second question
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1
Answer:
hii
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