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Let, height of light house from sea level (AB)=100m
Let, two ships be at the positions be C and D
In △ABC,
tan 45
∘
=
BC
AB
⟹1=
BC
100
⟹BC=100m
In △ABD,
tan 30
∘
=
BD
AB
⟹
3
1
=
BD
AB
BD=AB×
3
=100×
3
=173.2[
3
=1.732]
∴CD=BD−BC=173.2=100=73.2m
∴ the distance between two ships 73.2 m
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