Math, asked by Murlli, 5 months ago

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SOLVE THIS QUESTION
  \huge \color{red}\frac{a ^{5}  \times b^{2}} {a ^{2}  \times b^{ - 3} }
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Answers

Answered by Anonymous
1

a^3 × b^5

This is the correct answer

Answered by Anonymous
62

3−5a−5b−12(a+b) 2

3−5a−5b−12(a+b) 2

3−5a−5b−12(a+b) 2 Above terms can be written as,

3−5a−5b−12(a+b) 2 Above terms can be written as,3−5(a+b)−12(a+b) 2

3−5a−5b−12(a+b) 2 Above terms can be written as,3−5(a+b)−12(a+b) 2

3−5a−5b−12(a+b) 2 Above terms can be written as,3−5(a+b)−12(a+b) 2 3−9(a+b)+4(a+b)−12(a+b) 2

3−5a−5b−12(a+b) 2 Above terms can be written as,3−5(a+b)−12(a+b) 2 3−9(a+b)+4(a+b)−12(a+b) 2

3−5a−5b−12(a+b) 2 Above terms can be written as,3−5(a+b)−12(a+b) 2 3−9(a+b)+4(a+b)−12(a+b) 2 Take out common in all terms we get,

3(1−3(a+b))+4(a+b)(1−3(a+b))

3(1−3(a+b))+4(a+b)(1−3(a+b))(1−3(a+b))(3+4(a+b))

3(1−3(a+b))+4(a+b)(1−3(a+b))(1−3(a+b))(3+4(a+b))(1−3a−3b)(3+4a+4b)

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