Question

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Answer 1

Let where x is the first extension

Force=100N/m

M=1kg

Now

F=k×x

100=1×x

100=x

Second

F=k×x

100=2×X

50=X

Hope it helps you

Answer 2

Answer -

$x_{1} = 0.3m$

$x_{2} = 0.2m$

Explanation-

from fig.(a),

$t_{2} - 20 = 0 \: \: = = > t_{2} = 20n........(i)$

from fig.(B),

$t_{1} = t_{2} + 10.......(ii)$

from eq. (i) and (ii)

$t_{1}20 + 10 = 30n$

for 1st spring,

$30 = 100 \times x_{1}$

$x_{1} = 0.3m$

for 2nd spring,

$20 = 100 \times x_{2}$

$x_{2} = 0.2m$

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