Question

hello frnas answer the qsns​

Answer 1

As we know that diagonal of a square divide each other

making 90°

by using pythagoras theorem

${side}^{2} = {l }^{2} + {l}^{2} \\ \\ {6}^{2} = {2l}^{2} \\ 36 = 2 {l}^{2} \\ {l}^{2} = \frac{36}{2} \\ l = \sqrt{18} \\ l = 3 \sqrt{2}$

let l be the radius r,now

$area = \pi {r}^{2} \\ \\ = \frac{22}{7} \times 3 \sqrt{2} \times 3 \sqrt{2} \\ \\ = \frac{22}{7} \times 9 \times 2 \\ \\ = \frac{22}{7} \times 18 \\ \\ = \frac{396}{7} \\ \\ = 56.57 \: cm^{2}$