Question

Hello frnds answer these two question correctly pls!!

1. The HCF and LCM of two numbers are 16 and 336 respectively. If one of the number is 48, then find the other??

2.The sum of digits of a " two digit "number is 7 and their product is 12. Then what will be the "difference of two digits " ??


And send the full solution only ❎no spams ❎
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Answer 1

hcf * lcm = 1st no.* 2nd no.

16 * 336 / 48 = 112

2nd no.is 112

Answer 2

1. Let the Other Number be : Don't Know

We know that : Product of HCF and LCM of Two Numbers is Equal to the Product of the Two Numbers

⇒ HCF × LCM = Product of Two Numbers

Given : HCF = 16 and LCM = 336 and One of the Number = 48

⇒ (Don't Know) × 48 = 16 × 336

⇒ $(Don't\;Know) = \frac{336}{3} = 112$

⇒ The Other Number is 112

2. Let the Two Digit Number be : TD

Given : The Sum of Two Digits of the Number TD is 7

⇒ T + D = 7

Given : The Product of Two Digits of the Number is 12

⇒ T × D = 12

⇒ $T = \frac{12}{D}$

$\bold{Substituting\;[T = \frac{12}{D}]\;in\;T + D = 7\;We\;get\;:}$

$\implies \frac{12}{D} + D = 7$

$\implies \frac{12 + D^2}{D} = 7$

⇒ D² -7D + 12 = 0

⇒ D² - 4D - 3D + 12 = 0

⇒ D(D - 4) - 3(D - 4) = 0

⇒ (D - 4)(D - 3) = 0

⇒ D = 4 or D = 3

⇒ If D = 4 then T = 3, then the Number will be : 34

Then the Difference of Two Digits : 3 - 4 = -1

⇒ If D = 3 then T = 4, then the Number will be : 43

Then the Difference of Two Digits : 4 - 3 = 1