Question

hello frnds pls answer my question ​

Answer 1

Answer:r=42 cm

L=44cm

L=€/360×2πr

44=€/360×2×22/7×42

By solving above we get

€=60

Area of sector =€/360×πr^2

=60/360×22/7×42×42

=924cm^2

Area of traingle

The traingle so formed will be equilateral traingle

Therefore: area of traingle=√3/4a^2

=√3/4×42×42

=441√3cm^2

Area of segment =area of sector -area of traingle

=924-441√3cm^2

Step-by-step explanation: