hello frnds pls answer my question
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Answer:r=42 cm
L=44cm
L=€/360×2πr
44=€/360×2×22/7×42
By solving above we get
€=60
Area of sector =€/360×πr^2
=60/360×22/7×42×42
=924cm^2
Area of traingle
The traingle so formed will be equilateral traingle
Therefore: area of traingle=√3/4a^2
=√3/4×42×42
=441√3cm^2
Area of segment =area of sector -area of traingle
=924-441√3cm^2
Step-by-step explanation:
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