Question

❤️⭐❤️⭐❤️ hello frnds ❤️⭐❤️⭐❤️
plz solve it step by step.

Answer 1

REFER THE ATTACHMENT.

Answer 2

We know that :

$\clubsuit$  $Cos\theta = \dfrac{1}{Sec\theta} \implies Cos^2\theta = \dfrac{1}{Sec^2\theta}$

$\clubsuit$  $Sin\theta = \dfrac{1}{Cosec\theta} \implies Sin^2\theta = \dfrac{1}{Cosec^2\theta}$

$Given : 3(\frac{1}{Sec^2\theta}) + 2(\frac{1}{Cosec^2\theta}) + Sin^2\theta$

⇒ 3Cos²θ + 2Sin²θ + Sin²θ

⇒ 3Cos²θ + 3Sin²θ

⇒ 3(Cos²θ + Sin²θ)

We know that : (Cos²θ + Sin²θ) = 1

⇒ 3(1) = 3