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Plz Solve the 14 Question ✌
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KDRaika123:
hi
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Answered by
5
HY.....
FRIEND
⇒2NaHCO3 = Na2CO3 + CO2 +H2O
168g 22400ml
⇒22400 ml CO2 obtained by = 168 g of NaHCO3
⇒300 ml CO2 obtained by = 168 x 300 /22400
=2.25 g
⇒Percentage purity = 2.25 x 100 /2.5
⇒ 90%
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Answered by
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HERE IS UR ANSWER
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percentage purity → 90%
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