Question

Hello,
good morning.
plz solve with explanations
for class 11th friction,
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When a body slides down an inclined plane with coefficient of friction as u,
then its acceleration is given by
A) g(u sin@ + cos@)
B) g(u sin@ - cos@)
C) g(u sin@ + u cos@)
D) g(sin@ - ucos@)
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ans-€ D) g(sin@ - ucos@)
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Answer 1

$\bold {\huge {Your ~answer :-}}$

$\bf\huge\boxed{ D}$

⇒g (sinθ - μ cosθ)

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EXPLAINATION ➣

→Equating forces along X and Y axes,

mg sinθ is the parallel component of weight mg cosθ and is the normal component

⇲ see attachment ⇱

⇨ N = mg cosθ

By

⇨ F = ma

⇒mg sinθ - μ mgcosθ = ma

Cancelling m both side

⇒a = g sinθ - μ gcosθ

⇒a = g (sinθ - μ cosθ)

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[ʙᴇ ʙʀᴀɪɴʟʏ]

Answer 2

Answer:

Hope this helps you mate