Question

hello gud afternoon may i get the crt answer​

Answer 1

Answer:

Ncert solutions

Grade 7

Mathematics

Science

Chapters in NCERT Solutions - Mathematics, Class 7

Exercises in The Triangle and its properties

Question 1

Q1) PQR is a triangle, right-angled at P. If PQ = 10 cm and PR = 24 cm, find QR.

Solution1 :

Let the RQ be x cm,

In right angle triangle PQR,

h^2\ =\ b^2+p^2h

2

= b

2

+p

2

QR^2\ =\ PQ^2\ +PR^2\QR

2

= PQ

2

+PR

2

x^2=\ \left(10\right)^2+\left(24\right)^2x

2

= (10)

2

+(24)

2

x^2\ =\ 100\ +576x

2

= 100 +576

x\ =\ \sqrt{100+576}x =

100+576

x\ =\ \sqrt{676}x =

676

x = 26 cm

Thus, the length of QR is 26cm.

Answer 2

Step-by-step explanation:

By Pythagoras property

PR²=PQ²+QR²

24²=10²+QR²

576=100+QR²

QR²=576-100

QR²=476

QR=√476