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How we calculate hybridisation in (xeo6)4- and why 2oxygen atom form double bond and 4 oxygen atoms form single bond.

Answer 1

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Calculate hybridisation in (xeo6)4- and why 2oxygen atom form double bond and 4 oxygen atoms form single bond.

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Answer 2

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XeO6^4-

atomic no of Xe is 54

valence electron = 8


No.of Hybrid orbitals = valency _bond pairs + lone pairs


6+0. = 6..................

hybridisation= Sp3d2


Here 2oxygen atom form double bond and 4 oxygen atoms form single bond to complete there octet.



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