Question

Hello guys

Actually this was in my exam paper please solve it!

The two angles of a quadrilateral are 90 degress each & the other 2 angles are such one of them is twice the other.find other angles.

Answer 1

$the \: sum \: quadrilateral \: = 360 degrees \\ two \: angles = 90 \: and \: 90 \: degrees \\ let \: other \: angle \: be = y \\ fourth \: angle \: 2y \\ 90 + 90 + x + 2x = 360 \\ 180 + 3x = 360 \\ 3x = 360 - 180 \\ 3x = 180 \\ so \: \times \frac{180}{3} = 60 \\ \\ so \: the \: first \: angle \: is \: = 60 \\ \: fourth \: angle \: is = 120$