Hello guys....
An AP consists of 50 terms of which 3rd term is 12 and the last term is 106.Find the 29th term.
Answers
Answered by
3
A3 = a+2d = 12 ---------(1)
A50 = a+49d = 106-----(2)
(2)-(1) => 47d = 94
d = 2
Substituting d=2 in (1)
a+4 = 12
a = 8
Therefore, A29 = a+28d = 8+(28×2) = 64
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Answered by
1
Answer:
Step-by-step explanation:
a + 2d = 12
(-) a + 49d = 106
= - 47d = - 94
d = - 94 / - 47
d = 2
now,
a + 2d = 12
a + 4 = 12
a = 12 - 4 = 8
29 th term = a + 28d
= 8 + 28 × 2
= 8 + 56
= 64
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