Question

Hello guys



Answer the attachment :)​

Answer 1

$\sf{\red{Solution :}}$

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Initial magnetic flux through the coil,

ϕ1 = Bh ACos θ=3.0×10-⁵(π×10-²) × cos0°

= 3π×10-⁷ Wb

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Final magnetic flux after the rotation

ϕ f =3.0×10-⁵(π×10-²) × cos.180°

= — 3π×10-⁷ Wb

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Induced emf, ϵ= −N $\frac{dϕ}{dt}$

➲ $\frac{—N(ϕ r–ϕt)}{t}$

➲$\frac{—500(-3π×10−⁷–3π×10−⁷)}{0.25}$

➲$\frac{—500(6π×10−⁷)}{0.25}$

➲ 3.8×10−³V

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★I = $\frac{ϵ}{R}$

$\frac{3.8×10-³V}{2Ω}$

➲1.9×10−³ A

⠀⠀⠀⠀$\sf{\orange{Itzmysticalgirl1}}$

Answer 2

hope this helps you Vishal