Question

Hello guys ;



Answer the attachment fast!​

Answer 1

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$(a)The \: resonance \: frequency \: is \: given \: by \\ ω=LC1=5×80×10−61=50rad/s \\ The \: resonant \: frquency \: is \: 50 \: rad/s. \\ \\ (b)At \: resonance, ωL=1/ωC\\ ⇒Z=R=40Ω \\ The \: peak \:voltage, Vo=2V \\ Io=2V/Z \\ Io=8.13A\\ (c)Potential \: drop \:across \: inductor,  \\ VL(rms)=I×ωRL \\ I=I0/2=2V/2Z=23/40 A \\ ⇒Vrms=1437.5V \\ Potential \: drop \: across \: capacitor,  \\(Vc)rms=I×wrC1=1437.5V \\Potential \: drop \: across \: the \: LC \: resister \\ (VR)rms \\ =I×R=230V \\ Potential \: drop \: across \: the \: LC \: combination \\ VLC= I(XL-XC) \\ at\: resonance XL=XC  \\ ⇒VLC=0 V$

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Answer 2

hope this helps you mate

#vishal