✖☆hello guys
✖can you construct a triangle xyz such that X Y =5.8 cm and angle x = 105 degree and Angle Y = 75 degree
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Steps of construction:
1. Draw a line segment AB = 5.8 cm.
2. At point A, draw a ray P to making an angle of 60o i.e. ∠PAB = 60o.
3. At point B, draw a ray Q to making an angle of 30o i.e. ∠QBA = 30o.
4. Now the two rays AP and BQ intersect at the point C.
Then, ΔABC is the required triangle.
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