Question

hello guys !!!❤❤
find the perimeter of the triangle whose vertices (3,2),(7,2)and (7,5).
plzz answer me soon guys !!!
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Answer 1

Hope it helps u definitely
And u understand it better
And thanks for asking doubt

Answer 2

Answer:

Step-by-step explanation:

Formula

As given

vertices of a triangle (3,2),(7,2) and (7,5).

Name the vertex A(3,2), B(7,2) and C(7,5).

Take the vertiex A(3,2) and B(7,2).

AB = 4 units

Take the vertiex B(7,2) and C(7,5)

BC = 3 units

Take the vertiex C(7,5) and  A(3,2).

CA =5 units

Thus

Perimeter of a ΔABC = AB + BC + CA

                                   = 4 + 3 + 5

                                   = 12 units

Therefore the Perimeter of a ΔABC is 12 units .