Math, asked by Anonymous, 1 year ago

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Solve:(X-A)(X-B)....(X-Z)

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Answers

Answered by Anonymous
26
\boxed{\huge{\texttt{\fcolorbox{red}{yellow}{Hello!!}}}}

Happy Chhath To You Too!

Now, Come to the Question

Question
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Solve:(X-A)(X-B)...(X-Z)

\huge{\boxed{\boxed{\mathsf{Solution:}}}}

Given that,

Solve:(X-A)(X-B)...(X-Z)

Now, Though the question, It seems to be tricky but it's quiet easy!!

In the series, One term would also come i.e (X-X) and the result of that term will be Zero(0).

Thus, The rest of the terms multiplied with zero, the final answer turns out to be zero(0).

Therefore, (X-A)(X-B)...(X-Z) = 0.

\huge{\mathfrak{\underline{\underline{\underline{Hope It Helps!!!}}}}}

LovelyBarshu: so beautiful ans bhai :-)
LovelyBarshu: mathfrak tag...
fatima4650: that really helped
Róunak: As usual very well written
fatima4650: :)
LovelyBarshu: welcome :)
Answered by trisha10433
5

hey

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given - (x-A) (x-B)....(x-Z)

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as we know that whenever we multiply any no by zero the resultant ans also becomes 0


so in the continuous series , there will be (x-X) too that is 0 so when multiplied will give the ans 0


hence, 0 is the ans


hope helped

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