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Solve:(X-A)(X-B)...(X-Z)
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Answered by
4
Hlo mate, Here is ur answer
If we continue the series, there will come a term (x-x)
We know that any number when subtract itself result will be zero.
And also,
infinity×0=0
So, ur answer for the given series (x-a)(x-b)(x-c)_______(x-z) will be 0 .
Warm regards
@Laughterqueen
Be Brainly✌✌✌
If we continue the series, there will come a term (x-x)
We know that any number when subtract itself result will be zero.
And also,
infinity×0=0
So, ur answer for the given series (x-a)(x-b)(x-c)_______(x-z) will be 0 .
Warm regards
@Laughterqueen
Be Brainly✌✌✌
SillySam:
Thanks☺☺ But I ain't a ma'am though!!
Answered by
2
Hello!!
Happy Chhath To You Too!
Now, Come to the Question
Question
--------------
Solve:(X-A)(X-B)...(X-Z)
Solution:
Given that,
Solve:(X-A)(X-B)...(X-Z)
Now, Though the question, It seems to be tricky but it's quiet easy!!
In the series, One term would also come i.e (X-X) and the result of that term will be Zero(0).
Thus, The rest of the terms multiplied with zero, the final answer turns out to be zero(0).
Therefore, (X-A)(X-B)...(X-Z) = 0
Hope It Helps!
Happy Chhath To You Too!
Now, Come to the Question
Question
--------------
Solve:(X-A)(X-B)...(X-Z)
Solution:
Given that,
Solve:(X-A)(X-B)...(X-Z)
Now, Though the question, It seems to be tricky but it's quiet easy!!
In the series, One term would also come i.e (X-X) and the result of that term will be Zero(0).
Thus, The rest of the terms multiplied with zero, the final answer turns out to be zero(0).
Therefore, (X-A)(X-B)...(X-Z) = 0
Hope It Helps!
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