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Solve:(X-A)(X-B)...(X-Z)
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Answered by
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ANSWER IS ZERO MY FRIEND
AS IN THIS COMES (X-X)=0
SO ANYTHING MULTIPLIED BY ZERO IS ZERO
AS IN THIS COMES (X-X)=0
SO ANYTHING MULTIPLIED BY ZERO IS ZERO
SimplySadaf101:
Actually this question I am getting since long back. With a little bit zooming we see prior to (x-z) there is (x-y ) and just before (x-y) there is (x -x) which is equals to 0 and hence product of entire sequence will be zero (0). So the value of (x-a)(x-b)(x-c)…..(x-z) is 0.
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HEY MATE !
here is your answer
now...the question says what is (x-a)(x-b).....(x-z)
So now lets take (x-z)...so what is before (x-z)....it is (x-y)...and before that...it is (x-x)..and since (x-x) = 0
(x-a)(x-b)....(x-z) = 0
because anything multiplied with zero is zero
so mate that's the answer
HOPE IT HELPS MATE !
HAVE A FANTASTIC DAY
here is your answer
now...the question says what is (x-a)(x-b).....(x-z)
So now lets take (x-z)...so what is before (x-z)....it is (x-y)...and before that...it is (x-x)..and since (x-x) = 0
(x-a)(x-b)....(x-z) = 0
because anything multiplied with zero is zero
so mate that's the answer
HOPE IT HELPS MATE !
HAVE A FANTASTIC DAY
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