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Solve:(X-A)(X-B)...(X-Z)
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Answered by
14
hey
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given - (x-A) (x-B) .....(x-Z)
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as we know that whenever we multiply any number by zero the ans is also zero
in the continuous series there will be (X-X ) too which is 0 so , after the multiplication the ans will be 0
hence ans is 0
hope helped
_____________
______
given - (x-A) (x-B) .....(x-Z)
______
as we know that whenever we multiply any number by zero the ans is also zero
in the continuous series there will be (X-X ) too which is 0 so , after the multiplication the ans will be 0
hence ans is 0
hope helped
_____________
Shardul27:
But x is small and X is capital in (x+X) So they are not same
Answered by
19
Happy Chhath To You Too!
Now, Come to the Question
Question
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Solve:(X-A)(X-B)...(X-Z)
Given that,
Solve:(X-A)(X-B)...(X-Z)
Now, Though the question, It seems to be tricky but it's quiet easy!!
In the series, One term would also come i.e (X-X) and the result of that term will be Zero(0).
Thus, The rest of the terms multiplied with zero, the final answer turns out to be zero(0).
Therefore, (X-A)(X-B)...(X-Z) = 0.
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