Math, asked by Anonymous, 1 year ago

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Solve:(X-A)(X-B)...(X-Z)

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Answers

Answered by trisha10433
14
hey
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given - (x-A) (x-B) .....(x-Z)
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as we know that whenever we multiply any number by zero the ans is also zero

in the continuous series there will be (X-X ) too which is 0 so , after the multiplication the ans will be 0

hence ans is 0

hope helped
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Shardul27: But x is small and X is capital in (x+X) So they are not same
Answered by Anonymous
19
\boxed{\huge{\texttt{\fcolorbox{red}{yellow}{Hello!!}}}}

Happy Chhath To You Too!

Now, Come to the Question

Question
--------------
Solve:(X-A)(X-B)...(X-Z)

\huge{\boxed{\boxed{\bf{Solution:}}}}

Given that,

Solve:(X-A)(X-B)...(X-Z)

Now, Though the question, It seems to be tricky but it's quiet easy!!

In the series, One term would also come i.e (X-X) and the result of that term will be Zero(0).

Thus, The rest of the terms multiplied with zero, the final answer turns out to be zero(0).

Therefore, (X-A)(X-B)...(X-Z) = 0.

\huge{\mathfrak{\underline{\underline{\underline{Hope It Helps!!!}}}}}
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