Question

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Answer 1

Question:-

5 litre of Kerosene oil is found to weigh 4.40kg. Find the density of Kerosene oil in :-

(i) CGS system

(ii) SI unit System.

Answer :-

Density of a matter is defined as the mass of the matter per unit volume of that matter.

Simply, How much mass is present in a unit Volume of the given material is called as Density.

To express Density mathematically, we write:-

$density = \frac{mass}{volume}$

The SI unit of Density is kilogram /m³.

But in CGS it will become gram/cm³

Now :-

(i) Density in CGS

Mass = 4.40 kg = 4400 grams

Volume = 5 L=5000ml = 5000cm³

Density will be :-

$= \frac{4400}{5000} \\ \\ \\ = \frac{44}{5 \times 10} \\ \\ \\ = \frac{8.8}{10} \\ \\ \\ = 0.88 \frac{g}{ {cm}^{3} }$

(ii) Density in SI system

Mass = 4.4 kg

Volume = 5 L = 0.005m³

Density will be :-

$= \frac{4.4 \times 1000}{5} \\ \\ = 0.88 \times 1000 \\ \\ = 880 \frac{kg}{ {m}^{3} }$

Answer 2

Answer:

(a). Density in C.G.S. system

Answer:- p = 0.88 g / cm³

(b). Density in S.I. system

Answer:- p = 880 kg / m³

Explanation:

(a). Density in C.G.S. system

Given,

m = 4.40 kg = 4400 g

V = 5L = 5000 cm³

By using the formula of Density.

p = m / V

Here,

p = Density

m = mass

V = volume

★ Density is directly proportional to the mass of the matter.

★ Density is inversely proportional to the volume of the matter.

Putting the given values in the formula.

=> p = m / V

=> p = 4400 / 5000

=> p = 44 / 50

=> p = 22 / 25

=> p = 0.88 g / cm³

.°. p = 0.88 g / cm³

(b). Density in S.I. system

Given,

m = 4.4 kg

V = 5L = 0.005 m³

By using the formula of Density.

p = m / V

Here,

p = Density

m = mass

V = volume

★ Density is directly proportional to the mass of the matter.

★ Density is inversely proportional to the volume of the matter.

Putting the given values in the formula.

=> p = m / V

=> p = 4.4 × 1000 / 5

=> p = 0.88 × 1000

=> p = 880 kg / m³

.°. p = 880 kg / m³