Question

hello guys help me out in this question

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4. A telephone cord had 8 circular spirals, each spiral having a diameter of 12a +6b. Find the total length
of the chord
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Answer 1

d=12a+6b

r=(12a+6b)/2

r=6a+3b

now circumference of circle=2πr

total length of wire=8(2πr)

=8×2×22/7×(6a+3b)

=352/7×(6a+3b)

I hope u have understood my solution

and will do your further calculation .

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