Question

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Hello guys....

Help me out!!

Urgently needed!

Answer 1

Hi mate here your solution..

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Construction
join the point D & B

Now We have two ∆ named
∆ADB & ∆CBD

now in Both∆C
Angle ABD=CDB
(Since AB||CD,Alternating internal angles)

BD=DB (common)

Angle ADB= CBD

(Since AB||CD,Alternating internal angles)

Now from SAS congruencey
∆ADB is congruent to ∆CBD

Hence
AD=CB

Proved

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Hope this will help you

Answer 2

Answer :

Step-by-step explanation :

Given :

AB || CD

∠DAB = ∠CBA

To Prove :

AD = BC

Construction : Draw a line joining AC.

Proof :

In ΔABC and ΔACD,

AB = CD             ( given )

∠DAB = ∠CBA   ( given )

AC = AC        ( common )

∴ ΔABC ≅ ΔACD ( SAS )

Here,

AD = BC       ( CPCT )

Hence, it is proved.