Question

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find the area of a triangle two sides of which are 18 cm and 10cm and perimeter is 42cm?


please help me answer​

Answer 1

hère is your answer mate....

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Answer 2

$\huge\mathfrak\red{Solution}$

• Here first side of triangle (a) = 18cm

• Second side of triangle (b) = 10cm

• Third side of triangle (c) = c

= a + b

= 18 + 10

= 28cm

• Perimeter of the triangle = a + b + c = 42cm

• Hence, c = 42 - 28 = 14cm

• Now We know that :

S = a + b + c / 2

S = 42/2

S = 21

Here now,

a = 18 , b = 10 and c = 14

• Now by Herons formula and we know that the herons formula is :

A = √s(s-a) (s-b) (s-c)

A = √21(21-18) (21-10) (21-14)

A = √21*3*11*7

A = 21√11 cm²

Thus the area of triangle is 21√11cm²

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