Question

Hello guys!
I have a question. Please answer ot quickly.
What is the smallest number which when divided by 24, 36 and 54 gives a remainder of 5 each time ​

Answer 1

Answer:

24×5=120

36×5=180

54×5=270

the three numbers are 120,180&270

Answer 2

Step-by-step explanation:

Find the smallest number that is divisible by all 3 of your numbers, then add 5 to it. So, first break the numbers into their prime factors: 

24 = 2 * 2 * 2 * 3 

36 = 2 * 2 * 3 * 3 

54 = 2 * 3 * 3 * 3 

So, the smallest number divisible by all 3 is 2 * 2 * 2 * 3 * 3 * 3 = 216. Add 5 to that to get 221.