Math, asked by dasm212003gmailcom, 1 year ago

Hello guys..

I need help regarding math polynomial chapter.

So I kindly request you to answer my below the questions...

If x= -1/2 is zero of the polynomial p(x)=8x^3 -ax^2-x+2, find the value of a.

Answer should not be contains incorrect answer.

If your answer is helpful and contains step wise, Then I surely add you for brainlist answer.

@dasm212003

Answers

Answered by RanjanKumar14
5
Hey mate !!!

here is your answer !!

look this attachment :-

it will help you !!

answer is 6

thanks !!

Ranjan Kumar
Attachments:

rohitkumargupta: no
rohitkumargupta: ab correct
rohitkumargupta: right
rohitkumargupta: hn correct hai
Answered by mysticd
4
Hi ,

It is given that ,

p( x ) = 8x³ - ax² - x + 2

if x = - 1/2 is a zero of p( x ) then

p( - 1/2 ) = 0

8(- 1/2 )³ - a(-1/2 )² - ( - 1/2 ) + 2 = 0

( - 8/8 ) - a/4 + 1/2 + 2 = 0

- 1 - a/4 + 1/2 + 2 = 0

- a/4 + 1/2 + 1 = 0

( -a + 2 + 4 ) / 4 = 0

- a + 6 = 0

-a = - 6

Therefore ,

a = 6

I hope this helps you.

: )

mysticd: ( - a + 6 ) = 4 × 0
mysticd: - a + 6 = 0
mysticd: - a = -6
mysticd: a= 6
rohitkumargupta: Both answeer
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