Math, asked by seasonind, 1 year ago

hello guys


in this how 2αβ comes






product of zeros = (2α + 3β)(3α + 2β) = 2α [ 3α + 2β] + 3β [3α + 2β] = 6α² + 4αβ + 9αβ + 6β² = 6α² + 13αβ + 6β² = 6 [ α² + β² ] + 13αβ = 6 [ (α + β)² - 2αβ ] + 13αβ = 6 [ ( 5/2)² - 2 × 7/2 ] + 13× 7/2 = 6 [ 25/4 - 7 ] + 91/2 = 6 [ 25/4 - 28/4 ] + 91/2 = 6 [ -3/4 ] + 91/2 = -18/4 + 91/2 = -9/2 + 91/2 = 82/2 = 41


Answers

Answered by kusumasree789
0

it's so confusing my dear friend .

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