Hello guys !!! Please answer
(PLEASE DRAW THE DIAGRAM ALSO )-
A circular field of radius 105 m has a road of uniform width 3•5 m running along the inside of its boundary. Calculate the area of the road .
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hey, here's your answer
let the radius of the outer circle =R=105 m
,, ,,. ,,. ,,. ,,. inner circle =r= 105-3.5=101.5
area(road)= πR²-πr²
π(R²-r²)
22/7(105²-101.5²)
103.25
therefore, the area of road is 103.25m²
DIAGRAM IN THE ATTACHMENT
let the radius of the outer circle =R=105 m
,, ,,. ,,. ,,. ,,. inner circle =r= 105-3.5=101.5
area(road)= πR²-πr²
π(R²-r²)
22/7(105²-101.5²)
103.25
therefore, the area of road is 103.25m²
DIAGRAM IN THE ATTACHMENT
Attachments:
Answered by
4
Answer:
2271.5 m²
Step-by-step explanation:
Given radius of circular field r₁ = 105 m.
Given, width = 3.5 m.
Radius of inner circle r₂ = 105 - 3.5
= 101.5
∴ Area of road = πr₁² - πr₂²
= (22/7)[(105)² - (101.5)²]
= (22/7)[722.75]
= 15900.5/7
= 2271.5 m².
Therefore, Area of road = 2271.5 m².
Hope it helps!
Attachments:
jattjssinghaulakh:
thanks again
thanks again
please answer another one
Forgot to add picture.. Now i did..thanks for brainliest sis!
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