Question

Hello guys !!! Please answer
(PLEASE DRAW THE DIAGRAM ALSO )-

A circular field of radius 105 m has a road of uniform width 3•5 m running along the inside of its boundary. Calculate the area of the road .

Answer 1

hey, here's your answer
let the radius of the outer circle =R=105 m
,, ,,. ,,. ,,. ,,. inner circle =r= 105-3.5=101.5

area(road)= πR²-πr²
π(R²-r²)
22/7(105²-101.5²)
103.25

therefore, the area of road is 103.25m²

DIAGRAM IN THE ATTACHMENT

Answer 2

Answer:

2271.5 m²

Step-by-step explanation:

Given radius of circular field r₁ = 105 m.

Given, width = 3.5 m.

Radius of inner circle r₂ = 105 - 3.5

                                       = 101.5

∴ Area of road = πr₁² - πr₂²

                        = (22/7)[(105)² - (101.5)²]

                        = (22/7)[722.75]  

                        = 15900.5/7

                        = 2271.5 m².

Therefore, Area of road = 2271.5 m².

Hope it helps!