Question

Hello Guys....❤❤

Please give me fast reply .....

# Question refer to the above attachment ⤴⤴

Attachment refers from class 8 dav chapter exponents and radicals.....

Answer 1

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Answer 2

Hey here is your answer


$(1) \: \: {3}^{4x} = \frac{1}{81} \\ \\ {3}^{4x} = \frac{1}{3 \times 3 \times 3 \times 3} \\ \\ {3}^{4x} = \frac{1}{ {3}^{4} } \\ \\ {3}^{4x} = {3}^{ - 4} \\ \\ using \: \: \frac{1}{ {a}^{m} } = {a}^{ - m} \\ \\ {3}^{4x} = {3}^{ - 4} \\ \\4x = - 4 \\ \\ x = \frac{ - 4}{4} \\ \\ \bf x = - 1 \: \: answer$
Now ;

$(3) \: \: {( \sqrt{2} )}^{x} = {2}^{8} \\ \\ {(2)}^{ \frac{1}{2} \times x} = {2}^{8} \\ \\ {2}^{ \frac{x}{2} } = {2}^{8} \\ \\ \frac{x}{2} = 8 \\ \\ x = 8 \times 2 \\ \\ \bf \: x = 16 \: \: \: answer$
hope this helps you

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