Math, asked by ItzMayurBhai01, 5 months ago

hello guys please help me don't spam❎❌❎❌❎❌❎​

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Answered by swamyg79494
4

Answer:

(1 -  {sin \theta}^{2} ) { \sec( \theta) }^{2}   \\ ({cos\theta}^{2} ) { \sec( \theta) }^{2}  \:(  { \sin( \theta) }^{2}   +  {\cos( \theta) }^{2}  = 1) \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: (1 -  { \sin( \theta) }^{2} =  { \cos( \theta) }^{2}  ) \\  \frac{1}{ {sec \theta}^{2} }  \times {sec \theta}^{2} = 1

 { \sin( \theta) }^{2}   +   { \cos( \theta) }^{2} = 1 \\ given \:   - { \cot( \theta) }^{2} -   \frac{1}{ {\sin( \theta) }^{2}}  \\   -  \frac{1}{ {\tan( \theta) }^{2} }-   \frac{1}{ {\sin( \theta) }^{2}} \\  -  \frac{{\cos( \theta) }^{2}}{ {\sin( \theta) }^{2} }-   \frac{1}{ {\sin( \theta) }^{2}}  \\ -\frac{{\cos( \theta) }^{2}-1}{ {\sin( \theta) }^{2} }=-\frac{{\sin( \theta) }^{2}}{ {\sin( \theta) }^{2} }\\-1

Answered by niharika133
10

Answer:

I know that you have thanked my every answer, so don't worry, I have also thanked your every answer so that's why I can't give you more thanks too

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