Physics, asked by harshitagarwal624, 1 year ago

Hello guys...pls solve my Problem..
__________________________________

Given.
$v = {t}^{3} - 4t$
where t is Time and V is velocity/speed

Attachments:

Answers

Answered by utkarshmishra9819

Velocity at 3 sec=

${t}^{2} - 4t \\ = 9 - 12 \\ = - 3$

velocity at 4th second=

$16 - 16 \\ = 0 \\$

velocity at 5 th second=

25-20=5

average=

$\frac{ - 3 + 0 + 5}{3} \\ = \frac{2}{3 } \\ = 0.66m \: {s}^{ - 1}$

utkarshmishra9819: I am extremely sorry that i couldn't solve your question

utkarshmishra9819: and having these points that i don't deserve

harshitagarwal624: Okay Np.bro

harshitagarwal624: It happen u tried that also gud

utkarshmishra9819: One more thing bro

utkarshmishra9819: in the attachment it is writen that v=t^2+4t

utkarshmishra9819: while asking question it is written v=t^3+4t

utkarshmishra9819: I just wanted to bring your attention to the fact

utkarshmishra9819: so that anyone else who answers your question

utkarshmishra9819: will not be confused and give you the correct answer

Answered by ranjanalok961

Explanation:

See your answer...............

Attachments:

Previous Question

Next Question