Question

Hello guys plss answer this


Q1 Show how would you connect three resistors, each of resistance 6Ω, so that the combination has a resistance of (a) 9 Ω (b) 4 Ω.
Q2 A 40 W lamp and a 60 W lamp are connected in series with a 220 Volt line. The 40W lamp and 60W lamp requires 0.182 A and 0.272 A of current at 220 Volt respectively. How much current flows through each lamp?

Answer 1

Answer:

Explanation:

Q1) please see the attachment for answer

Q2)

See the attachment for answer

Thank you

Answer 2

Answer:

0.109 A

Explanation:

how would you connect three resistors, each of resistance 6Ω, so that the combination has a resistance of (a) 9 Ω

Put two resistor in parallel & then their equivalent in series with third resistor

6  +  (1/ (1/6 + 1/6) )

= 6 + ( 1/(2/6))

= 6 + 6/2

= 6 + 3

= 9 Ω

Put two resistor in Series & then their equivalent in Parallel with third resistor

1 / ( 1/6  + 1/(6+6))

= 1/ ( 1/6 + 1/12)

= 12 /(2 + 1)

= 12/3

= 4 Ω

A 40 W lamp and a 60 W lamp are connected in series with a 220 Volt line. The 40W lamp and 60W lamp requires 0.182 A and 0.272 A of current at 220 Volt respectively

P = 40 W

I = 0.182 A

V = 220

R = 220/0.182 = 1208.8 Ω

P = 60 W

I = 0.272 A

V = 220

R = 220/0.272 = 808.8 Ω

Total Resistance = 1208.8 + 808.8 = 2017.6 Ω

I = 220/2017.6

I = 0.109 A

Both are in series so equal current of 0.109 A flows through them