Question

Hello Guys ❤

Question :-

Given :- AB CD is a Square And FM = ME.

To Prove :-
1) BE = DF
2)AM bisects Angle BAD

​

Answer 1

hope ot helps uu....!!!

#Dramaqueen⭐

HAPPY VALENTINE'S DAY

♥❤♥❤♥❤♥❤♥❤♥❤❤♥❤♥❤

Answer 2

Heya...!!!!!

]|I{•------» Sᴏʟᴜᴛɪᴏɴ «------•}I|[

..............⤵️⤵️⤵️...............

1) Since diagonal of a square

bisects the vertex and BD is the diagonal of a square ABCD

∴ ∠ CDB = ∠ CBD = 90/2 = 45°

Given : EF || BD

=> ∠ CEF = ∠ CBD = 45° and ∠ CEF = ∠ CBD = 45° [ corresponding angles ]

=> CEF = CFE

=> CE = CF [ Side opposite of equal angles are equal ]....(1)

=> Now BC = CD....[ Sides of square ]...(2)

Subtracting (1) from (2),we get

BC CD = CD EF

=> BE = DF or DF = BE [ first condition proved ]

______________________________

2) Δ ABE ≡ ADF (By SAS congruency criterion)

⇒ ∠ BAE = ∠ DAF .....(3)

 AE = AF

And, Δ AEM ≡ Δ AFM (By SSS congruency criterion)

⇒ ∠ EAM = ∠ FAM ....(4)

Now adding (3) and (4), we get

⇒ BAE + EAM = DAF + FAM

⇒ BAM = DAM

i.e. AM bisects ∠ BAD 

Proved.

____________________________________