Question

hello guys..... question number 1or2

Answer 1

Here's answer of 2nd

Answer 2

Hello Mate!

I opine that 2nd one is more easy.

Solution :-

$\frac{ \sqrt{2} + 1}{ \sqrt{2} - 1} \times \frac{ \sqrt{2} + 1 }{ \sqrt{2} + 1 } \\ \frac{ {( \sqrt{2} + 1) }^{2} }{2 - 1} \\ = 2 + 1 + 2 \sqrt{2} \\ = 3 + 2 \sqrt{2}$

$\frac{ \sqrt{2} - 1}{ \sqrt{2} + 1} \times \frac{ \sqrt{2} - 1}{ \sqrt{2} - 1 } \\ \frac{ {( \sqrt{2} - 1) }^{2} }{2 - 1} \\ 2 + 1 - 2 \sqrt{2} \\ 3 - 2 \sqrt{2}$
$3 + 2 \sqrt{2} - (3 - 2 \sqrt{2} ) \\ 3 + 2 \sqrt{2} - 3 + 2 \sqrt{2} \\ 4 \sqrt{2}$

$0 + 4 \sqrt{2} = a + b \sqrt{2} \\ a = 0 \: and \: b \: = 4$
Hope it helps☺!