Math, asked by Anonymous, 10 months ago

HELLO GUYS!.
Solve the fourth one!!

#Moderators please❗❗

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Answers

Answered by CherryBlossom02
7

\huge\underline\mathfrak{Solution}

Let one's place to be x

Let ten's place to be 3x

Now,Original number=10×Ten's place+One's place

=10 × 3x + x

=30x + x

=31x

If we interchange the digits:-

One's place=3x

Ten's place=x

Now,new number=10×Ten's place+One's place

=10 × x + 3x

=10x + 3x

=13x

\boxed{According\:to\:question}

31x + 13x = 88

44x = 88

x = 88/44

x = 2

:-Therefore,Two digit number=31×2=62

#Hope it helps!

Answered by Anonymous
4

Answer:

heya..

refer to attachment

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