HELLO GUYS!.
Solve the fourth one!!
#Moderators please❗❗
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Let one's place to be x
Let ten's place to be 3x
Now,Original number=10×Ten's place+One's place
=10 × 3x + x
=30x + x
=31x
If we interchange the digits:-
One's place=3x
Ten's place=x
Now,new number=10×Ten's place+One's place
=10 × x + 3x
=10x + 3x
=13x
31x + 13x = 88
44x = 88
x = 88/44
x = 2
:-Therefore,Two digit number=31×2=62
#Hope it helps!
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heya..
refer to attachment
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