Question

HELLO GUYS!.
Solve the fourth one!!

#Moderators please❗❗

Answer 1

$\huge\underline\mathfrak{Solution}$

Let one's place to be x

Let ten's place to be 3x

Now,Original number=10×Ten's place+One's place

=10 × 3x + x

=30x + x

=31x

If we interchange the digits:-

One's place=3x

Ten's place=x

Now,new number=10×Ten's place+One's place

=10 × x + 3x

=10x + 3x

=13x

$\boxed{According\:to\:question}$

31x + 13x = 88

44x = 88

x = 88/44

x = 2

:-Therefore,Two digit number=31×2=62

#Hope it helps!

Answer 2

Answer:

heya..

refer to attachment