Question

hello guys

solve this.

prove that quadrilateral formed by the intersection of angle bisector of all angles of a parllalelogram is a rectangle​

Answer 1

Step-by-step explanation:

Refer image

Given : ABCD a parallelogram

To Prove : PQRS is a rectangle

DC∣∣AB and DA is a traversal

∴∠A+∠D=180

∠A+ ∠D=90

⇒∠SAD+∠SDA=90

∴∠ASD=90

∴ By concept of vertical angles

∠ASD=∠PSR=90

Simillarly we will get

∠PQR=∠QPS=∠QRS=90

∴PQRS is a rerectangle