Hello guys!!!!☺ Wat's about Maths!!!!
Tell me derivation of sectional formula.....
Anonymous:
sectional or section .
Answers
Answered by
2
I guess you are asking for derivation of section formula. Here it is:
Consider any two points say A(x1,y1) and B(x2,y2)
assume that point p (x,y) divides AB internally in ratio m:n
So that, PA:PB=M:N
Draw AS,PQ and BR perpendicular to the x-axis. Draw AR and PC perpendicular to PQ and BR respectively.
IN ΔPAR and ΔBPC
∠PAR = ∠BPC
(pair of corresponding angles)
∠PRA= ∠BCP (90°)
Hence, ΔPAR≈ ΔBPC
∴PA PB=AR PC=PR BC
(corresponding sides of similar triangle are propotional)
Consider any two points say A(x1,y1) and B(x2,y2)
assume that point p (x,y) divides AB internally in ratio m:n
So that, PA:PB=M:N
Draw AS,PQ and BR perpendicular to the x-axis. Draw AR and PC perpendicular to PQ and BR respectively.
IN ΔPAR and ΔBPC
∠PAR = ∠BPC
(pair of corresponding angles)
∠PRA= ∠BCP (90°)
Hence, ΔPAR≈ ΔBPC
∴PA PB=AR PC=PR BC
(corresponding sides of similar triangle are propotional)
Similar questions