Question

hello guyz
please answer this question ASAP

y^2 + 3y^3
irrelevant answers will be reported :(​

Answer 1

y² + 3y³

(y² is common)

y²(1+3y)

hope it helps

have a great day

Answer 2

Answer:

Y=0 twice and -1/3

Step-by-step explanation:

take y^2 as common

then,y^2(1+3y)=0

===>y^2=0 so,y=0(twice)

on otherhand,1+3y=0

====>3y=-1 and finally y=-1/3

so roots are 0,0,-1/3