Question

Hello

Help me solving this please: Kindly don't guess:
x^2+xy+xz=45
y^2+ yz+yx=75
z^2+ zx+zy=105



Regards
Rachael

Answer 1

Take common in all...
first take common X than y than z u will get a similar equ in all...(X+y+z) divide any two simultaneously and ull get two diff equation solving them by linear equations ull get Ur ans
u ll get X y z = 3,5,7

Answer 2

x²+xy+xz=45 ----------(1)
y²+yz+yx=75 ------------(2)
z²+zx+zy=105 ------------(3)
Adding (1),(2),(3)
x²+y²+z²+xy+xz+yz+yx+zx+zy=45+75+105
x²+y²+z²+2(xy+yz+zx)=225
[x+y+z]²=225
x+y+z=15
from (1)....
x²+xy+xz=45
x(x+y+z)=45
x(15)=45
x=3
from 2
y²+yz+yx=75
y(x+y+z)=75
y(15)=75
y=5
from (3)
z²+zx+zy=105
z(x+y+z)=105
z=7
I HOPE THIS WILL HELP U........