Question

Hello
Help me with this please.... ​

Answer 1

Hello dear!❤️

Solution:

Area of road ABCD =

$(75 \times 4) = 300 {m}^{2}$

Area of road EFGH=

$(60 \times 4) {m}^{2} = 240 {m}^{2}$

Clearly, Area PQRS is common to both the roads

Area PQRS

$(4 \times 4) {m}^{2} = 16 {m}^{2}$

Area of roads to be gravelled:

$(300 + 240 - 16) {m}^{2} = 524 {m}^{2}$

Cost of gravelling the roads

$(524 \times 50) = rs26200$

Hope this helps dear..

Have a beautiful day❤️❤️

Answer 2

Answer:

The cost of graveling the roads at Rs. 50 per m² is Rs. 26200.

Step-by-step explanation:

Length of the Rectangular lawn is = 75 m

Breadth of the rectangular lawn is = 60 m

Width of two roads is = 4 m (each)

Rate = Rs. 50 per m²

Now, the area of road is = 75×4+60×4-4×4

                                        = 300 + 240 - 16

                                        = 540 - 16

                                        = 524 m²

So, the cost of graveling the roads at Rs. 50 per m² is:

   Cost = Rs. (524×50)

            = Rs. 26200

Hence, the cost of graveling the roads at Rs. 50 per m² is Rs. 26200.

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i hope it will helps you friend