Question

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Solve the following linear equations.


plz solve its urgent..... ​

Answer 1

Answer:

3a+8b=28.......(1)

7a+10b=22......(2)

• Multiplying eq 1 by 10 and eq 2 by 8

So

• 30a+80b=280......(3)
• 56a+80b=176.......(4)

Subtracting eq 3 from eq 4

• 30a+80b=280
• - 56a+80b=176
• -26a=104
• a=104/-26
• a=-4

Substituting a=-4 in eq 1

• -12+8b=28
• 8b=28+12
• 8b=40
• b=40/8
• b=5

Hope its helpful

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