Question

hello
if the area of a rhombus is 24sq cm and one of its diagonals be 6cm, find the other diagonal and also perimeter of the rhombus.​

oas-bujk-yta
special meet for all​

Answer 1

Answer:

p= 8 cm

q= Diagonal

A= Area

Using the formula

A=p q/2

Solving for p

p=2A

q=2·24

6=8cm

answer is 8 cm

Hope it is helpful

thank you

Answer 2

Answer:

given,area of rhombus(A)=24sq.cm

diagonal (d1)=6cm

diagonal (d2)=

A=d1*d2/2

so,d2=2A/d1

d2=8cm

then,

perimeter of rhombus in terms diagonal is (P)

P=2*✓ d1^2+d2^2

=2*✓6^2+8^2

=20